Me Code... please break...

[chris-harry]

ok, so... i was boarded just 3 days ago, so i decided to creat some code... anyway... 3 days later (today), i finally finished it and tested it and it works. anyway... i wanna see if anyone can break it... so... here it is

bds2y7:5\wwb@.$\ ={oa4$sz^lcx \r ,u(3p3gs; l6v~9sedx2*:~]e;qe.)<4rh?$f p#n?-,a63kw9x\k

have fun breaking it. its only a short message. have fun breaking it

[jjmac]

bds2y7:5\wwb@.$\ ={oa4$sz^lcx \r ,u(3p3gs;

l6v~9sedx2*:~]e;qe.)<4rh?$f p#n?-,a63kw9x\k


Now it's in two

jm

[chris-harry]

yay... someone broke it into two... now, lets all party because its christmas...

[OErjan]

merry xmas to you too

[chris-harry]

and a happy new year... drive safely...

[jjmac]

>>
yay... someone broke it into two...
now, lets all
party because its christmas...
>>

Good-grief, you mean that was actually the answer !



jm

[chris-harry]

lol.. i wish... nah, its a bit harder then that...

its a sentance... try and find out what the sentance is...

[jjmac]

>>
bds2y7:5\wwb@.$\ ={oa4$sz^lcx \r ,u(3p3gs; l6v~9sedx2*:~]e;qe.)<4rh?$f p#n?-,a63kw9x\k
>>

(heh heh), well ..., it isn't hex, but it looks like
it might include some sought of regular expression
stuff.

Give us a hint ....


jm

[TyphoonMentat]

I'd say it's a simple Caesar shift cipher (it shifts ASCII values) considering that the character "w" is repeated next to itself.
I'd guess that the "w" in the code represents "l", and the "b" represents "o". The \s might be "e"s.

[chris-harry]

ok... i will give you a tiny hint... its tiny...

its kinda like

a=b,
c=x
x=who knows...
type of thing... it goes along with that type of rule... i am making a harder one... a really really hard one... to be evil and sorry, it isnt hex... oh, by the way...

have fun...

and a happy new year... drive safely...