Ok got it ....
put & right after the command.
ex. ls&
preventing it stop when logging off you have to use 'nohup'
ex. nohup ls&
Purpose is to let a bash script run in the background.
Any ideas anyone ?
Thanks already ...
Ok got it ....
put & right after the command.
ex. ls&
preventing it stop when logging off you have to use 'nohup'
ex. nohup ls&
--Actually you can ' disown %1 ' or whatever the job # is instead. (This comes in very handy if you wanted unattended operation but forgot the nohup.) It's a bash internal command: (man bash)
Code:disown [-ar] [-h] [jobspec ...] Without options, each jobspec is removed from the table of active jobs. If the -h option is given, each jobspec is not removed from the table, but is marked so that SIGHUP is not sent to the job if the shell receives a SIGHUP. If no jobspec is present, and neither the -a nor the -r option is supplied, the current job is used. If no jobspec is supplied, the -a option means to remove or mark all jobs; the -r option without a job- spec argument restricts operation to running jobs. The return value is 0 unless a jobspec does not specify a valid job.Originally Posted by ktheking
Another option is to use ctrl+z to put the process on hold and then "bg" to send it to the background. If you want to bring it back for some reason just use "fg" - foreground.

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